What are the solutions to the equation x^3-2x^2+3=3x^2+5x-22 ?

The solutions to the equation x^3-2x^2+3=3x^2+5x-22 are x=5,x=-sqrt(5),x=sqrt(5)

Find the zeros of x^3-2x^2+3=3x^2+5x-22

The zeros of x^3-2x^2+3=3x^2+5x-22 are x=5,x=-sqrt(5),x=sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 2 x^{2} + 3 = 3 x^{2} + 5 x - 22

x = 5, x = - 5, x = 5

Decimal Notation

x = 5, x = - 2.23606 \dots, x = 2.23606 \dots

Solution steps

x^{3} - 2 x^{2} + 3 = 3 x^{2} + 5 x - 22

Move

22

to the left side

x^{3} - 2 x^{2} + 25 = 3 x^{2} + 5 x

Move

5 x

to the left side

x^{3} - 2 x^{2} + 25 - 5 x = 3 x^{2}

Move

3 x^{2}

to the left side

x^{3} - 5 x^{2} - 5 x + 25 = 0

Factor

x^{3} - 5 x^{2} - 5 x + 25 : (x - 5) (x + 5) (x - 5)

(x - 5) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = 5, x = - 5, x = 5

x^{6} + x^{5} - 2 x^{4} = 0

x^{3} + 9 x^{2} + 27 x + 23 = 0

x^{4} = - (- x^{2})^{2}

(x^{4})^{2} = 16 - 15 (x^{2})^{2}

x^{4} - x^{3} - x^{2} - 1 = 0

What are the solutions to the equation x^3-2x^2+3=3x^2+5x-22 ?
The solutions to the equation x^3-2x^2+3=3x^2+5x-22 are x=5,x=-sqrt(5),x=sqrt(5)
Find the zeros of x^3-2x^2+3=3x^2+5x-22
The zeros of x^3-2x^2+3=3x^2+5x-22 are x=5,x=-sqrt(5),x=sqrt(5)