What are the solutions to the equation 9x^3+9=0 ?

The solutions to the equation 9x^3+9=0 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i

Find the zeros of 9x^3+9=0

The zeros of 9x^3+9=0 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i

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9 x^{3} + 9 = 0

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

Solution steps

9 x^{3} + 9 = 0

Move

9

to the right side

9 x^{3} = - 9

Divide both sides by

9

x^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

x^{3} + 5 x^{2} + 2 x - 8 = x^{2} + 3 x - 4

(3 w - 21) (w^{2} + 9 w + 20) = 0

y, 34 x - y^{3} = 23 x - 9

0 = x^{3} + x + 1

2 x^{4} - 4 x^{3} - 2 x^{2} = 0

What are the solutions to the equation 9x^3+9=0 ?
The solutions to the equation 9x^3+9=0 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i
Find the zeros of 9x^3+9=0
The zeros of 9x^3+9=0 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i