What are the solutions to the equation -2x(x+1)(x^2+49)=0 ?

The solutions to the equation -2x(x+1)(x^2+49)=0 are x=0,x=-1,x=7i,x=-7i

Find the zeros of -2x(x+1)(x^2+49)=0

The zeros of -2x(x+1)(x^2+49)=0 are x=0,x=-1,x=7i,x=-7i

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- 2 x (x + 1) (x^{2} + 49) = 0

x = 0, x = - 1, x = 7 i, x = - 7 i

Solution steps

- 2 x (x + 1) (x^{2} + 49) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x^{2} + 49 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} + 49 = 0 : x = 7 i, x = - 7 i

The solutions are

x = 0, x = - 1, x = 7 i, x = - 7 i

x, y^{2} = (x + 4)^{3}

(4 x^{4}) + 5 = (4 - 4)

x^{3} + 8 x^{2} + 19 x + 12 = 0

40000 = 15000 (1 + x)^{5}

x, x^{4} - 10 x^{2} + 29 = 8

What are the solutions to the equation -2x(x+1)(x^2+49)=0 ?
The solutions to the equation -2x(x+1)(x^2+49)=0 are x=0,x=-1,x=7i,x=-7i
Find the zeros of -2x(x+1)(x^2+49)=0
The zeros of -2x(x+1)(x^2+49)=0 are x=0,x=-1,x=7i,x=-7i