What are the solutions to the equation 2x^3+8x^2-24x=0 ?

The solutions to the equation 2x^3+8x^2-24x=0 are x=0,x=2,x=-6

Find the zeros of 2x^3+8x^2-24x=0

The zeros of 2x^3+8x^2-24x=0 are x=0,x=2,x=-6

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2 x^{3} + 8 x^{2} - 24 x = 0

x = 0, x = 2, x = - 6

Solution steps

2 x^{3} + 8 x^{2} - 24 x = 0

Factor

2 x^{3} + 8 x^{2} - 24 x : 2 x (x - 2) (x + 6)

2 x (x - 2) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x + 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 6 = 0 : x = - 6

The solutions are

x = 0, x = 2, x = - 6

x^{3} - 8 x^{2} + 9 x + 18 = 0

- 15 y^{4} = (D) (3 y^{2})

x^{6} + x^{3} - 42 = 0

6 y^{2} + 9 y = 15 y^{3}

x^{3} + 3 x^{2} - 4 x + 12 = 0

What are the solutions to the equation 2x^3+8x^2-24x=0 ?
The solutions to the equation 2x^3+8x^2-24x=0 are x=0,x=2,x=-6
Find the zeros of 2x^3+8x^2-24x=0
The zeros of 2x^3+8x^2-24x=0 are x=0,x=2,x=-6