What are the solutions to the equation 2x^3-13x^2+22x-8=0 ?

The solutions to the equation 2x^3-13x^2+22x-8=0 are x=2,x= 1/2 ,x=4

Find the zeros of 2x^3-13x^2+22x-8=0

The zeros of 2x^3-13x^2+22x-8=0 are x=2,x= 1/2 ,x=4

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2 x^{3} - 13 x^{2} + 22 x - 8 = 0

x = 2, x = \frac{1}{2}, x = 4

Decimal Notation

x = 2, x = 0.5, x = 4

Solution steps

2 x^{3} - 13 x^{2} + 22 x - 8 = 0

Factor

2 x^{3} - 13 x^{2} + 22 x - 8 : (x - 2) (2 x - 1) (x - 4)

(x - 2) (2 x - 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x - 1 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x - 4 = 0 : x = 4

The solutions are

x = 2, x = \frac{1}{2}, x = 4

x, y = x^{3} + 3

0 = x^{3} - 6 x^{2} + 32

x, y = x^{3} - 1

3 \cdot (x^{3} - 1) = - 27

(x - 2)^{3} = - x + 4

What are the solutions to the equation 2x^3-13x^2+22x-8=0 ?
The solutions to the equation 2x^3-13x^2+22x-8=0 are x=2,x= 1/2 ,x=4
Find the zeros of 2x^3-13x^2+22x-8=0
The zeros of 2x^3-13x^2+22x-8=0 are x=2,x= 1/2 ,x=4