What are the solutions to the equation solvefor y,5(y+1)^3+x^2=1 ?

The solutions to the equation solvefor y,5(y+1)^3+x^2=1 are

Find the zeros of solvefor y,5(y+1)^3+x^2=1

The zeros of solvefor y,5(y+1)^3+x^2=1 are

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solve for

y, 5 (y + 1)^{3} + x^{2} = 1

Solution steps

5 (y + 1)^{3} + x^{2} = 1

Move

x^{2}

to the right side

5 (y + 1)^{3} = 1 - x^{2}

Divide both sides by

5

(y + 1)^{3} = \frac{1 - x ^{2}}{5}

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

0 = 24 x^{3} + 2 x^{2} + x - 5

25 x^{4} - 65 x^{2} + 36 = 0

24 = r^{4}

x, x^{5} = y^{4}

x, x^{4} - 1 + y = 0

What are the solutions to the equation solvefor y,5(y+1)^3+x^2=1 ?
The solutions to the equation solvefor y,5(y+1)^3+x^2=1 are
Find the zeros of solvefor y,5(y+1)^3+x^2=1
The zeros of solvefor y,5(y+1)^3+x^2=1 are