What are the solutions to the equation (4x^2+1)^2=0 ?

The solutions to the equation (4x^2+1)^2=0 are x= 1/2 i,x=-1/2 i

Find the zeros of (4x^2+1)^2=0

The zeros of (4x^2+1)^2=0 are x= 1/2 i,x=-1/2 i

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(4 x^{2} + 1)^{2} = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

(4 x^{2} + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

4 x^{2} + 1 = 0 : x = \frac{1}{2} i, x = - \frac{1}{2} i

The solutions are

x = \frac{1}{2} i, x = - \frac{1}{2} i

45 = 30 (1 + x)^{3}

60 x^{4} - 180 x^{3} + 120 x^{2} = 0

x (x + 2) (x - 3) + 3 = 0

x^{3} - 16 x^{2} + 64 x = 0

16 x^{4} - 145 x^{2} + 324 = 0

What are the solutions to the equation (4x^2+1)^2=0 ?
The solutions to the equation (4x^2+1)^2=0 are x= 1/2 i,x=-1/2 i
Find the zeros of (4x^2+1)^2=0
The zeros of (4x^2+1)^2=0 are x= 1/2 i,x=-1/2 i