What are the solutions to the equation x^3+x^2-22x-40=0 ?

The solutions to the equation x^3+x^2-22x-40=0 are x=-2,x=-4,x=5

Find the zeros of x^3+x^2-22x-40=0

The zeros of x^3+x^2-22x-40=0 are x=-2,x=-4,x=5

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x^{3} + x^{2} - 22 x - 40 = 0

x = - 2, x = - 4, x = 5

Solution steps

x^{3} + x^{2} - 22 x - 40 = 0

Factor

x^{3} + x^{2} - 22 x - 40 : (x + 2) (x + 4) (x - 5)

(x + 2) (x + 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 4 = 0 or x - 5 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 4 = 0 : x = - 4

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 2, x = - 4, x = 5

30 π r^{2} + 4 π r^{3} = 4500

2 m^{3} - 250 = 0

7 x^{4} + 2 = 8 x^{4} + 10

4 x^{3} + 16 x^{2} + 19 x + 5 = 0

- x^{3} - 3 x^{2} + 32 x - 60 = 0

What are the solutions to the equation x^3+x^2-22x-40=0 ?
The solutions to the equation x^3+x^2-22x-40=0 are x=-2,x=-4,x=5
Find the zeros of x^3+x^2-22x-40=0
The zeros of x^3+x^2-22x-40=0 are x=-2,x=-4,x=5