What are the solutions to the equation (x+1)(x+1)(x+1)=0 ?

The solutions to the equation (x+1)(x+1)(x+1)=0 are x=-1

Find the zeros of (x+1)(x+1)(x+1)=0

The zeros of (x+1)(x+1)(x+1)=0 are x=-1

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(x + 1) (x + 1) (x + 1) = 0

x = - 1

Solution steps

(x + 1) (x + 1) (x + 1) = 0

Simplify

(x + 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x + 1 = 0 : x = - 1

The solution is

x = - 1

x^{3} - 3 x^{2} - 24 x + 90 = 0

a^{15} = \frac{1}{4}

x, x^{6} - 8 x^{3} - 9 = 0

(- 20 b^{4}) \cdot (b b^{2} b) = 0

x = 3.25 x^{3} - 6 x^{2} + 7 x - 88

What are the solutions to the equation (x+1)(x+1)(x+1)=0 ?
The solutions to the equation (x+1)(x+1)(x+1)=0 are x=-1
Find the zeros of (x+1)(x+1)(x+1)=0
The zeros of (x+1)(x+1)(x+1)=0 are x=-1