What are the solutions to the equation (-20b^4)*(bb^2b)=0 ?

The solutions to the equation (-20b^4)*(bb^2b)=0 are b=0

Find the zeros of (-20b^4)*(bb^2b)=0

The zeros of (-20b^4)*(bb^2b)=0 are b=0

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(- 20 b^{4}) \cdot (b b^{2} b) = 0

b = 0

Solution steps

(- 20 b^{4}) (b b^{2} b) = 0

Simplify

- 20 b^{8} = 0

Divide both sides by

- 20

\frac{- 20 b ^{8}}{- 20} = \frac{0}{- 20}

b^{8} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0

The solution is

b = 0

x = 3.25 x^{3} - 6 x^{2} + 7 x - 88

3 x^{2} - 12 x^{4} = 0

X^{3} = 30 3^{3} + 40 4^{3} + 50 5^{3}

(u^{2} - 6 u + 8) (2 u + 14) = 0

X^{4} - X^{2} + 1 = 0

What are the solutions to the equation (-20b^4)*(bb^2b)=0 ?
The solutions to the equation (-20b^4)*(bb^2b)=0 are b=0
Find the zeros of (-20b^4)*(bb^2b)=0
The zeros of (-20b^4)*(bb^2b)=0 are b=0