What are the solutions to the equation x^3-2x^2-14x+28=0 ?

The solutions to the equation x^3-2x^2-14x+28=0 are x=2,x=-sqrt(14),x=sqrt(14)

Find the zeros of x^3-2x^2-14x+28=0

The zeros of x^3-2x^2-14x+28=0 are x=2,x=-sqrt(14),x=sqrt(14)

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x^{3} - 2 x^{2} - 14 x + 28 = 0

x = 2, x = - 14, x = 14

Decimal Notation

x = 2, x = - 3.74165 \dots, x = 3.74165 \dots

Solution steps

x^{3} - 2 x^{2} - 14 x + 28 = 0

Factor

x^{3} - 2 x^{2} - 14 x + 28 : (x - 2) (x + 14) (x - 14)

(x - 2) (x + 14) (x - 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 14 = 0 or x - 14 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 14 = 0 : x = - 14

Solve

x - 14 = 0 : x = 14

The solutions are

x = 2, x = - 14, x = 14

x, (2 x + 1)^{4} - 80 = 1

x^{4} - 2 x^{3} + x^{2} - 2 = 0

x^{6} - 7 x^{3} + 10 = 0

4 x^{3} = 16 x^{2} - 48 x

- x^{3} + 8 x^{2} - 13 x + 2 = 0

What are the solutions to the equation x^3-2x^2-14x+28=0 ?
The solutions to the equation x^3-2x^2-14x+28=0 are x=2,x=-sqrt(14),x=sqrt(14)
Find the zeros of x^3-2x^2-14x+28=0
The zeros of x^3-2x^2-14x+28=0 are x=2,x=-sqrt(14),x=sqrt(14)