What are the solutions to the equation 10x(x^2-4)^4=0 ?

The solutions to the equation 10x(x^2-4)^4=0 are x=0,x=-2,x=2

Find the zeros of 10x(x^2-4)^4=0

The zeros of 10x(x^2-4)^4=0 are x=0,x=-2,x=2

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10 x (x^{2} - 4)^{4} = 0

x = 0, x = - 2, x = 2

Solution steps

10 x (x^{2} - 4)^{4} = 0

Factor

10 x (x^{2} - 4)^{4} : 10 x (x + 2)^{4} (x - 2)^{4}

10 x (x + 2)^{4} (x - 2)^{4} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 2, x = 2

6 x^{3} + 6 x^{2} - 7 x + 2 = 0

(x - 2) (x + 8) (x - 1) = 0

r^{5} + 2 r^{3} + 10 r^{2} + r + 10 = 0

8 x^{3} + 2 x - 2 = 0

x^{2} - 4 = - x^{3} + 6

What are the solutions to the equation 10x(x^2-4)^4=0 ?
The solutions to the equation 10x(x^2-4)^4=0 are x=0,x=-2,x=2
Find the zeros of 10x(x^2-4)^4=0
The zeros of 10x(x^2-4)^4=0 are x=0,x=-2,x=2