What are the solutions to the equation (x-2)(x+8)(x-1)=0 ?

The solutions to the equation (x-2)(x+8)(x-1)=0 are x=2,x=-8,x=1

Find the zeros of (x-2)(x+8)(x-1)=0

The zeros of (x-2)(x+8)(x-1)=0 are x=2,x=-8,x=1

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(x - 2) (x + 8) (x - 1) = 0

x = 2, x = - 8, x = 1

Solution steps

(x - 2) (x + 8) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 8 = 0 or x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 8 = 0 : x = - 8

Solve

x - 1 = 0 : x = 1

The solutions are

x = 2, x = - 8, x = 1

r^{5} + 2 r^{3} + 10 r^{2} + r + 10 = 0

8 x^{3} + 2 x - 2 = 0

x^{2} - 4 = - x^{3} + 6

0.11 = (1 + \frac{r}{12})^{12} - 1

(- 1 - x)^{2} (- 1 - 2 x - x^{2})^{2} = 0

What are the solutions to the equation (x-2)(x+8)(x-1)=0 ?
The solutions to the equation (x-2)(x+8)(x-1)=0 are x=2,x=-8,x=1
Find the zeros of (x-2)(x+8)(x-1)=0
The zeros of (x-2)(x+8)(x-1)=0 are x=2,x=-8,x=1