What are the solutions to the equation (-1-x)^2(-1-2x-x^2)^2=0 ?

The solutions to the equation (-1-x)^2(-1-2x-x^2)^2=0 are x=-1

Find the zeros of (-1-x)^2(-1-2x-x^2)^2=0

The zeros of (-1-x)^2(-1-2x-x^2)^2=0 are x=-1

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(- 1 - x)^{2} (- 1 - 2 x - x^{2})^{2} = 0

x = - 1

Solution steps

(- 1 - x)^{2} (- 1 - 2 x - x^{2})^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 1 - x = 0 or - 1 - 2 x - x^{2} = 0

Solve

- 1 - x = 0 : x = - 1

Solve

- 1 - 2 x - x^{2} = 0 : x = - 1

The solution is

x = - 1

x (x^{2} - 9) = 0

x^{3} (22 - (\frac{x}{2})) = 18

4 x (x - 1)^{2} = 1

(x + 1) (x + 2)^{2} (x^{2} - 6 x + 10) = 0

4 x^{3} - 3 x = 0

What are the solutions to the equation (-1-x)^2(-1-2x-x^2)^2=0 ?
The solutions to the equation (-1-x)^2(-1-2x-x^2)^2=0 are x=-1
Find the zeros of (-1-x)^2(-1-2x-x^2)^2=0
The zeros of (-1-x)^2(-1-2x-x^2)^2=0 are x=-1