What are the solutions to the equation (x+1)(x+2)^2(x^2-6x+10)=0 ?

The solutions to the equation (x+1)(x+2)^2(x^2-6x+10)=0 are x=-1,x=-2,x=3+i,x=3-i

Find the zeros of (x+1)(x+2)^2(x^2-6x+10)=0

The zeros of (x+1)(x+2)^2(x^2-6x+10)=0 are x=-1,x=-2,x=3+i,x=3-i

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(x + 1) (x + 2)^{2} (x^{2} - 6 x + 10) = 0

x = - 1, x = - 2, x = 3 + i, x = 3 - i

Solution steps

(x + 1) (x + 2)^{2} (x^{2} - 6 x + 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x^{2} - 6 x + 10 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} - 6 x + 10 = 0 : x = 3 + i, x = 3 - i

The solutions are

x = - 1, x = - 2, x = 3 + i, x = 3 - i

4 x^{3} - 3 x = 0

s^{3} = 1000

(2 A + 1) A^{66} = 0

(r - 1)^{2} (r + 1)^{3} = 0

2 x^{3} + x^{2} - 6 x - 7 = 2 x^{2} + 3 x - 7

What are the solutions to the equation (x+1)(x+2)^2(x^2-6x+10)=0 ?
The solutions to the equation (x+1)(x+2)^2(x^2-6x+10)=0 are x=-1,x=-2,x=3+i,x=3-i
Find the zeros of (x+1)(x+2)^2(x^2-6x+10)=0
The zeros of (x+1)(x+2)^2(x^2-6x+10)=0 are x=-1,x=-2,x=3+i,x=3-i