What are the solutions to the equation 150^2+400^2=y^2 ?

The solutions to the equation 150^2+400^2=y^2 are y=50sqrt(73),y=-50sqrt(73)

Find the zeros of 150^2+400^2=y^2

The zeros of 150^2+400^2=y^2 are y=50sqrt(73),y=-50sqrt(73)

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15 0^{2} + 40 0^{2} = y^{2}

y = 5073, y = - 5073

Decimal Notation

y = 427.20018 \dots, y = - 427.20018 \dots

Solution steps

15 0^{2} + 40 0^{2} = y^{2}

Switch sides

y^{2} = 15 0^{2} + 40 0^{2}

Simplify

15 0^{2} + 40 0^{2} : 182500

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 182500, y = - 182500

182500 = 5073

- 182500 = - 5073

y = 5073, y = - 5073

- 8 + 2

x^{2} + 2 x = 2

\frac{( x - 1 ) \cdot ( x + 2 )}{12} - \frac{( x + 1 ) \cdot ( x - 2 )}{6} - 1 = \frac{x - 3}{3}

\frac{1}{12 m ^{3} n} + \frac{8}{22 m ^{2} n ^{2}}

3 (4 c + 1) - 4 (4 c - 3)

What are the solutions to the equation 150^2+400^2=y^2 ?
The solutions to the equation 150^2+400^2=y^2 are y=50sqrt(73),y=-50sqrt(73)
Find the zeros of 150^2+400^2=y^2
The zeros of 150^2+400^2=y^2 are y=50sqrt(73),y=-50sqrt(73)