What are the solutions to the equation x^2+2x=2 ?

The solutions to the equation x^2+2x=2 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of x^2+2x=2

The zeros of x^2+2x=2 are x=-1+sqrt(3),x=-1-sqrt(3)

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x^{2} + 2 x = 2

x = - 1 + 3, x = - 1 - 3

Decimal Notation

x = 0.73205 \dots, x = - 2.73205 \dots

Solution steps

x^{2} + 2 x = 2

Move

2

to the left side

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

\frac{( x - 1 ) \cdot ( x + 2 )}{12} - \frac{( x + 1 ) \cdot ( x - 2 )}{6} - 1 = \frac{x - 3}{3}

\frac{1}{12 m ^{3} n} + \frac{8}{22 m ^{2} n ^{2}}

3 (4 c + 1) - 4 (4 c - 3)

(\frac{4}{9})^{\frac{1}{2}}

x (a - 7) - y (a - 7)

What are the solutions to the equation x^2+2x=2 ?
The solutions to the equation x^2+2x=2 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of x^2+2x=2
The zeros of x^2+2x=2 are x=-1+sqrt(3),x=-1-sqrt(3)