What are the solutions to the equation 2x^4+4x^2=0 ?

The solutions to the equation 2x^4+4x^2=0 are x=0,x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of 2x^4+4x^2=0

The zeros of 2x^4+4x^2=0 are x=0,x=sqrt(2)i,x=-sqrt(2)i

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2 x^{4} + 4 x^{2} = 0

x = 0, x = 2 i, x = - 2 i

Solution steps

2 x^{4} + 4 x^{2} = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

2 u^{2} + 4 u = 0

Solve

2 u^{2} + 4 u = 0 : u = 0, u = - 2

u = 0, u = - 2

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 0 : x = 0

Solve

x^{2} = - 2 : x = 2 i, x = - 2 i

The solutions are

x = 0, x = 2 i, x = - 2 i

36 x - 24 x^{2} + 4 x^{3} = 0

x^{3} - x^{2} + x + 39 = 0

t^{3} - 8 = 0

x^{8} = 46

x^{8} = 48

What are the solutions to the equation 2x^4+4x^2=0 ?
The solutions to the equation 2x^4+4x^2=0 are x=0,x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of 2x^4+4x^2=0
The zeros of 2x^4+4x^2=0 are x=0,x=sqrt(2)i,x=-sqrt(2)i