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What are the solutions to the equation 2x^4-21x^2+45=0 ?
The solutions to the equation 2x^4-21x^2+45=0 are x=sqrt(15/2),x=-sqrt(15/2),x=sqrt(3),x=-sqrt(3)Find the zeros of 2x^4-21x^2+45=0
The zeros of 2x^4-21x^2+45=0 are x=sqrt(15/2),x=-sqrt(15/2),x=sqrt(3),x=-sqrt(3)