What are the solutions to the equation 4x^3+x^2-36x-9=0 ?

The solutions to the equation 4x^3+x^2-36x-9=0 are x=-1/4 ,x=-3,x=3

Find the zeros of 4x^3+x^2-36x-9=0

The zeros of 4x^3+x^2-36x-9=0 are x=-1/4 ,x=-3,x=3

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4 x^{3} + x^{2} - 36 x - 9 = 0

x = - \frac{1}{4}, x = - 3, x = 3

Solution steps

4 x^{3} + x^{2} - 36 x - 9 = 0

Factor

4 x^{3} + x^{2} - 36 x - 9 : (4 x + 1) (x + 3) (x - 3)

(4 x + 1) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - \frac{1}{4}, x = - 3, x = 3

(x + 2) (x - 1) (x - 3) = - 3

m^{3} = 2

- x^{3} + x^{2} + 14 x + 11 = 0

2 x^{2} x - 3 x - 20 = 0

(x - 1)^{6} + (x - 2)^{6} = 1

What are the solutions to the equation 4x^3+x^2-36x-9=0 ?
The solutions to the equation 4x^3+x^2-36x-9=0 are x=-1/4 ,x=-3,x=3
Find the zeros of 4x^3+x^2-36x-9=0
The zeros of 4x^3+x^2-36x-9=0 are x=-1/4 ,x=-3,x=3