What are the solutions to the equation 4x^3-7x^2-2x=0 ?

The solutions to the equation 4x^3-7x^2-2x=0 are x=0,x=-1/4 ,x=2

Find the zeros of 4x^3-7x^2-2x=0

The zeros of 4x^3-7x^2-2x=0 are x=0,x=-1/4 ,x=2

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4 x^{3} - 7 x^{2} - 2 x = 0

x = 0, x = - \frac{1}{4}, x = 2

Solution steps

4 x^{3} - 7 x^{2} - 2 x = 0

Factor

4 x^{3} - 7 x^{2} - 2 x : x (4 x + 1) (x - 2)

x (4 x + 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x + 1 = 0 or x - 2 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - \frac{1}{4}, x = 2

2 x^{3} + 2 x^{2} + 2 x + 1 = 0

x^{3} - 3 x = 3

v^{3} = 1

v^{3} = 2

(2)^{2} = (x) (x + 1)^{2}

What are the solutions to the equation 4x^3-7x^2-2x=0 ?
The solutions to the equation 4x^3-7x^2-2x=0 are x=0,x=-1/4 ,x=2
Find the zeros of 4x^3-7x^2-2x=0
The zeros of 4x^3-7x^2-2x=0 are x=0,x=-1/4 ,x=2