What are the solutions to the equation (m-1)^2(m^2+1)^2=0 ?

The solutions to the equation (m-1)^2(m^2+1)^2=0 are m=1,m=i,m=-i

Find the zeros of (m-1)^2(m^2+1)^2=0

The zeros of (m-1)^2(m^2+1)^2=0 are m=1,m=i,m=-i

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(m - 1)^{2} (m^{2} + 1)^{2} = 0

m = 1, m = i, m = - i

Solution steps

(m - 1)^{2} (m^{2} + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m - 1 = 0 or m^{2} + 1 = 0

Solve

m - 1 = 0 : m = 1

Solve

m^{2} + 1 = 0 : m = i, m = - i

The solutions are

m = 1, m = i, m = - i

x^{3} + 6 x + 9 x = 0

2 x^{4} = 128 x

x, 2 x y - x^{3} = 0

- 2 x^{3} + 3 = 0

3 x^{4} + 4 x^{3} + 6 x^{2} - 4 = 0

What are the solutions to the equation (m-1)^2(m^2+1)^2=0 ?
The solutions to the equation (m-1)^2(m^2+1)^2=0 are m=1,m=i,m=-i
Find the zeros of (m-1)^2(m^2+1)^2=0
The zeros of (m-1)^2(m^2+1)^2=0 are m=1,m=i,m=-i