What are the solutions to the equation x^4+3x^3-3x^2-7x+6=0 ?

The solutions to the equation x^4+3x^3-3x^2-7x+6=0 are x=1,x=-2,x=-3

Find the zeros of x^4+3x^3-3x^2-7x+6=0

The zeros of x^4+3x^3-3x^2-7x+6=0 are x=1,x=-2,x=-3

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x^{4} + 3 x^{3} - 3 x^{2} - 7 x + 6 = 0

x = 1, x = - 2, x = - 3

Solution steps

x^{4} + 3 x^{3} - 3 x^{2} - 7 x + 6 = 0

Factor

x^{4} + 3 x^{3} - 3 x^{2} - 7 x + 6 : (x - 1)^{2} (x + 2) (x + 3)

(x - 1)^{2} (x + 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 1, x = - 2, x = - 3

(2 x - 5)^{5} = 243

x^{4} + 16 i = 0

2 x^{3} - 3 x^{2} - 36 x = 0

x^{5} + 2 x - 7 = 50

u^{4} - u^{2} + 1 = 0

What are the solutions to the equation x^4+3x^3-3x^2-7x+6=0 ?
The solutions to the equation x^4+3x^3-3x^2-7x+6=0 are x=1,x=-2,x=-3
Find the zeros of x^4+3x^3-3x^2-7x+6=0
The zeros of x^4+3x^3-3x^2-7x+6=0 are x=1,x=-2,x=-3