What are the solutions to the equation 2x^3-3x^2-36x=0 ?

The solutions to the equation 2x^3-3x^2-36x=0 are x=0,x=(3+3sqrt(33))/4 ,x=(3-3sqrt(33))/4

Find the zeros of 2x^3-3x^2-36x=0

The zeros of 2x^3-3x^2-36x=0 are x=0,x=(3+3sqrt(33))/4 ,x=(3-3sqrt(33))/4

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2 x^{3} - 3 x^{2} - 36 x = 0

x = 0, x = \frac{3 + 3 33}{4}, x = \frac{3 - 3 33}{4}

Solution steps

2 x^{3} - 3 x^{2} - 36 x = 0

Factor

2 x^{3} - 3 x^{2} - 36 x : x (2 x^{2} - 3 x - 36)

x (2 x^{2} - 3 x - 36) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x^{2} - 3 x - 36 = 0

Solve

2 x^{2} - 3 x - 36 = 0 : x = \frac{3 + 3 33}{4}, x = \frac{3 - 3 33}{4}

The solutions are

x = 0, x = \frac{3 + 3 33}{4}, x = \frac{3 - 3 33}{4}

x^{5} + 2 x - 7 = 50

u^{4} - u^{2} + 1 = 0

3 x^{4} + 26 = 19 x^{2}

0 = x^{4} + 4 x + 3

x (x^{2} + 5 x + 8) = 0

What are the solutions to the equation 2x^3-3x^2-36x=0 ?
The solutions to the equation 2x^3-3x^2-36x=0 are x=0,x=(3+3sqrt(33))/4 ,x=(3-3sqrt(33))/4
Find the zeros of 2x^3-3x^2-36x=0
The zeros of 2x^3-3x^2-36x=0 are x=0,x=(3+3sqrt(33))/4 ,x=(3-3sqrt(33))/4