What are the solutions to the equation x(x^2+5x+8)=0 ?

The solutions to the equation x(x^2+5x+8)=0 are x=0,x=-5/2+i(sqrt(7))/2 ,x=-5/2-i(sqrt(7))/2

Find the zeros of x(x^2+5x+8)=0

The zeros of x(x^2+5x+8)=0 are x=0,x=-5/2+i(sqrt(7))/2 ,x=-5/2-i(sqrt(7))/2

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x (x^{2} + 5 x + 8) = 0

x = 0, x = - \frac{5}{2} + i \frac{7}{2}, x = - \frac{5}{2} - i \frac{7}{2}

Solution steps

x (x^{2} + 5 x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 5 x + 8 = 0

Solve

x^{2} + 5 x + 8 = 0 : x = - \frac{5}{2} + i \frac{7}{2}, x = - \frac{5}{2} - i \frac{7}{2}

The solutions are

x = 0, x = - \frac{5}{2} + i \frac{7}{2}, x = - \frac{5}{2} - i \frac{7}{2}

x^{3} - 9 x^{2} + 14 x = 0

- 12 x^{2} (x^{3} + 2) = 0

x^{3} + 2 x - 42 = 0

50 (1 + r)^{12} = 10

x, x^{3} - x^{2} - 10 x - 8 = 0

What are the solutions to the equation x(x^2+5x+8)=0 ?
The solutions to the equation x(x^2+5x+8)=0 are x=0,x=-5/2+i(sqrt(7))/2 ,x=-5/2-i(sqrt(7))/2
Find the zeros of x(x^2+5x+8)=0
The zeros of x(x^2+5x+8)=0 are x=0,x=-5/2+i(sqrt(7))/2 ,x=-5/2-i(sqrt(7))/2