What are the solutions to the equation 4x^{14}-57=37 ?

The solutions to the equation 4x^{14}-57=37 are x=\sqrt[14]{47/2},x=-\sqrt[14]{47/2}

Find the zeros of 4x^{14}-57=37

The zeros of 4x^{14}-57=37 are x=\sqrt[14]{47/2},x=-\sqrt[14]{47/2}

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4 x^{14} - 57 = 37

Decimal Notation

x = 1.25294 \dots, x = - 1.25294 \dots

Solution steps

4 x^{14} - 57 = 37

Move

57

to the right side

4 x^{14} = 94

Divide both sides by

4

x^{14} = \frac{47}{2}

For

x^{n} = f (a)

, n is even, the solutions are

52 x^{6} = x - 23 x

51 = 4 x^{4} - 13

x^{3} - 4 x = 5

x^{4} - 2 x^{2} - 3 x - 2 = 0

x^{4} - 4 x^{3} + 7 x^{2} - 6 x - 18 = 0

What are the solutions to the equation 4x^{14}-57=37 ?
The solutions to the equation 4x^{14}-57=37 are x=\sqrt[14]{47/2},x=-\sqrt[14]{47/2}
Find the zeros of 4x^{14}-57=37
The zeros of 4x^{14}-57=37 are x=\sqrt[14]{47/2},x=-\sqrt[14]{47/2}