What are the solutions to the equation 51=4x^4-13 ?

The solutions to the equation 51=4x^4-13 are x=2,x=-2,x=2i,x=-2i

Find the zeros of 51=4x^4-13

The zeros of 51=4x^4-13 are x=2,x=-2,x=2i,x=-2i

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51 = 4 x^{4} - 13

x = 2, x = - 2, x = 2 i, x = - 2 i

Solution steps

51 = 4 x^{4} - 13

Switch sides

4 x^{4} - 13 = 51

Move

13

to the right side

4 x^{4} = 64

Divide both sides by

4

x^{4} = 16

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = 16

Solve

u^{2} = 16 : u = 16, u = - 16

u = 16, u = - 16

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 16 : x = 2, x = - 2

Solve

x^{2} = - 16 : x = 2 i, x = - 2 i

The solutions are

x = 2, x = - 2, x = 2 i, x = - 2 i

x^{3} - 4 x = 5

x^{4} - 2 x^{2} - 3 x - 2 = 0

x^{4} - 4 x^{3} + 7 x^{2} - 6 x - 18 = 0

x^{3} - 5 x^{2} = - 4 x

3 x^{6} - 14 x^{3} = 80

What are the solutions to the equation 51=4x^4-13 ?
The solutions to the equation 51=4x^4-13 are x=2,x=-2,x=2i,x=-2i
Find the zeros of 51=4x^4-13
The zeros of 51=4x^4-13 are x=2,x=-2,x=2i,x=-2i