What are the solutions to the equation 4x^2(x-1)+2x(x-1)=0 ?

The solutions to the equation 4x^2(x-1)+2x(x-1)=0 are x=0,x=1,x=-1/2

Find the zeros of 4x^2(x-1)+2x(x-1)=0

The zeros of 4x^2(x-1)+2x(x-1)=0 are x=0,x=1,x=-1/2

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4 x^{2} (x - 1) + 2 x (x - 1) = 0

x = 0, x = 1, x = - \frac{1}{2}

Solution steps

4 x^{2} (x - 1) + 2 x (x - 1) = 0

Factor

4 x^{2} (x - 1) + 2 x (x - 1) : 2 x (x - 1) (2 x + 1)

2 x (x - 1) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or 2 x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions are

x = 0, x = 1, x = - \frac{1}{2}

5 x^{4} - 1 2^{3} = 0

(x + 1) (x - 2)^{2} = 0

π \cdot r^{4} = 4.86 \cdot 1 0^{- 7}

x^{4} - 265 x^{2} + 1 = 0

x^{4} x - 8 = 2 x - 4

What are the solutions to the equation 4x^2(x-1)+2x(x-1)=0 ?
The solutions to the equation 4x^2(x-1)+2x(x-1)=0 are x=0,x=1,x=-1/2
Find the zeros of 4x^2(x-1)+2x(x-1)=0
The zeros of 4x^2(x-1)+2x(x-1)=0 are x=0,x=1,x=-1/2