What are the solutions to the equation 5x^4-12^3=0 ?

The solutions to the equation 5x^4-12^3=0 are

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5x^4-12^3=0

5 x^{4} - 1 2^{3} = 0

Solution steps

5 x^{4} - 1 2^{3} = 0

Move

1 2^{3}

to the right side

5 x^{4} = 1728

Divide both sides by

5

x^{4} = \frac{1728}{5}

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = \frac{1728}{5}

Solve

u^{2} = \frac{1728}{5} : u = \frac{1728}{5}, u = - \frac{1728}{5}

u = \frac{1728}{5}, u = - \frac{1728}{5}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = - \frac{1728}{5} : x = - \frac{24 3}{5}, x = - - \frac{24 3}{5}

The solutions are

(x + 1) (x - 2)^{2} = 0

π \cdot r^{4} = 4.86 \cdot 1 0^{- 7}

x^{4} - 265 x^{2} + 1 = 0

x^{4} x - 8 = 2 x - 4

x (x^{2} + x - 6) = 0

What are the solutions to the equation 5x^4-12^3=0 ?
The solutions to the equation 5x^4-12^3=0 are
Find the zeros of 5x^4-12^3=0
The zeros of 5x^4-12^3=0 are