What are the solutions to the equation x(x^2+x-6)=0 ?

The solutions to the equation x(x^2+x-6)=0 are x=0,x=2,x=-3

Find the zeros of x(x^2+x-6)=0

The zeros of x(x^2+x-6)=0 are x=0,x=2,x=-3

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x (x^{2} + x - 6) = 0

x = 0, x = 2, x = - 3

Solution steps

x (x^{2} + x - 6) = 0

Factor

x (x^{2} + x - 6) : x (x - 2) (x + 3)

x (x - 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x + 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 0, x = 2, x = - 3

- 2 = 2 x^{5} + x^{3} + 1

(2 - x^{2})^{2} - 1 = 0

m^{4} - 13 m^{2} + 36 = 0

z^{4} + 3 z^{2} + 2 = 0

x^{4} - 5 x^{2} - 6 = 0

What are the solutions to the equation x(x^2+x-6)=0 ?
The solutions to the equation x(x^2+x-6)=0 are x=0,x=2,x=-3
Find the zeros of x(x^2+x-6)=0
The zeros of x(x^2+x-6)=0 are x=0,x=2,x=-3