What are the solutions to the equation -2=2x^5+x^3+1 ?

The solutions to the equation -2=2x^5+x^3+1 are x=-1

Find the zeros of -2=2x^5+x^3+1

The zeros of -2=2x^5+x^3+1 are x=-1

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- 2 = 2 x^{5} + x^{3} + 1

x = - 1

Solution steps

- 2 = 2 x^{5} + x^{3} + 1

Switch sides

2 x^{5} + x^{3} + 1 = - 2

Move

2

to the left side

2 x^{5} + x^{3} + 3 = 0

Factor

2 x^{5} + x^{3} + 3 : (x + 1) (2 x^{4} - 2 x^{3} + 3 x^{2} - 3 x + 3)

(x + 1) (2 x^{4} - 2 x^{3} + 3 x^{2} - 3 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x^{4} - 2 x^{3} + 3 x^{2} - 3 x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x^{4} - 2 x^{3} + 3 x^{2} - 3 x + 3 = 0 :

No Solution for

x \in R

The solution is

x = - 1

(2 - x^{2})^{2} - 1 = 0

m^{4} - 13 m^{2} + 36 = 0

z^{4} + 3 z^{2} + 2 = 0

x^{4} - 5 x^{2} - 6 = 0

x^{3} - x^{2} - 8 x - 12 = 0

What are the solutions to the equation -2=2x^5+x^3+1 ?
The solutions to the equation -2=2x^5+x^3+1 are x=-1
Find the zeros of -2=2x^5+x^3+1
The zeros of -2=2x^5+x^3+1 are x=-1