What are the solutions to the equation x^3-4x=2x ?

The solutions to the equation x^3-4x=2x are x=0,x=-sqrt(6),x=sqrt(6)

Find the zeros of x^3-4x=2x

The zeros of x^3-4x=2x are x=0,x=-sqrt(6),x=sqrt(6)

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x^{3} - 4 x = 2 x

x = 0, x = - 6, x = 6

Decimal Notation

x = 0, x = - 2.44948 \dots, x = 2.44948 \dots

Solution steps

x^{3} - 4 x = 2 x

Move

2 x

to the left side

x^{3} - 6 x = 0

Factor

x^{3} - 6 x : x (x + 6) (x - 6)

x (x + 6) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 6 = 0 or x - 6 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

The solutions are

x = 0, x = - 6, x = 6

- 32 x^{2} + 4 x^{3} - x + 8 = 0

z, z^{4} - 9 = 0

- (x - 1)^{3} = 8

- (x - 1)^{3} = 0

(p^{8})^{2} = p^{10}

What are the solutions to the equation x^3-4x=2x ?
The solutions to the equation x^3-4x=2x are x=0,x=-sqrt(6),x=sqrt(6)
Find the zeros of x^3-4x=2x
The zeros of x^3-4x=2x are x=0,x=-sqrt(6),x=sqrt(6)