What are the solutions to the equation 0.12=x^4-1 ?

The solutions to the equation 0.12=x^4-1 are

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0.12=x^4-1

0.12 = x^{4} - 1

Solution steps

0.12 = x^{4} - 1

Switch sides

x^{4} - 1 = 0.12

Move

1

to the right side

x^{4} = 1.12

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = 1.12

Solve

u^{2} = 1.12 : u = 1.12, u = - 1.12

u = 1.12, u = - 1.12

Substitute back

u = x^{2},

solve for

x

Solve

The solutions are

x, x^{4} + 7 x^{2} - 16 = 0

- x^{3} + 8 x - 3 = 0

8 x^{7} - 7 x^{8} = 0.75

x^{3} - 2 x^{2} + 3 = 0

(8 + x)^{3} = 64

What are the solutions to the equation 0.12=x^4-1 ?
The solutions to the equation 0.12=x^4-1 are
Find the zeros of 0.12=x^4-1
The zeros of 0.12=x^4-1 are