What are the solutions to the equation m^3=125 ?

The solutions to the equation m^3=125 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i

Find the zeros of m^3=125

The zeros of m^3=125 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i

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m^{3} = 125

m = 5, m = - \frac{5}{2} + \frac{5 3}{2} i, m = - \frac{5}{2} - \frac{5 3}{2} i

Solution steps

m^{3} = 125

For

x^{3} = f (a)

the solutions are

Simplify

m = 5, m = - \frac{5}{2} + \frac{5 3}{2} i, m = - \frac{5}{2} - \frac{5 3}{2} i

5 x^{3} - 3 x - 1 = 0

16 x^{4} = 1048576

- (a + 1)^{2} (a - 8) = 0

x^{2} + 6 x + 9 = 4 x^{4}

m^{7} - 3 = 0

What are the solutions to the equation m^3=125 ?
The solutions to the equation m^3=125 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i
Find the zeros of m^3=125
The zeros of m^3=125 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i