What are the solutions to the equation 2x^3+3x^2-2x-3=0 ?

The solutions to the equation 2x^3+3x^2-2x-3=0 are x=-3/2 ,x=-1,x=1

Find the zeros of 2x^3+3x^2-2x-3=0

The zeros of 2x^3+3x^2-2x-3=0 are x=-3/2 ,x=-1,x=1

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2 x^{3} + 3 x^{2} - 2 x - 3 = 0

x = - \frac{3}{2}, x = - 1, x = 1

Solution steps

2 x^{3} + 3 x^{2} - 2 x - 3 = 0

Factor

2 x^{3} + 3 x^{2} - 2 x - 3 : (2 x + 3) (x + 1) (x - 1)

(2 x + 3) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x + 1 = 0 or x - 1 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - \frac{3}{2}, x = - 1, x = 1

3 w - w^{3} = 2

x^{5} = 1 0^{35}

y^{3} y - 5 = 19

x^{4} + 8 x - 8 = 0

x^{4} - 4 x^{3} - 7 x^{2} + 22 x + 24 = 0

What are the solutions to the equation 2x^3+3x^2-2x-3=0 ?
The solutions to the equation 2x^3+3x^2-2x-3=0 are x=-3/2 ,x=-1,x=1
Find the zeros of 2x^3+3x^2-2x-3=0
The zeros of 2x^3+3x^2-2x-3=0 are x=-3/2 ,x=-1,x=1