What are the solutions to the equation -3x^3+2x^2+x=0 ?

The solutions to the equation -3x^3+2x^2+x=0 are x=0,x=-1/3 ,x=1

Find the zeros of -3x^3+2x^2+x=0

The zeros of -3x^3+2x^2+x=0 are x=0,x=-1/3 ,x=1

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- 3 x^{3} + 2 x^{2} + x = 0

x = 0, x = - \frac{1}{3}, x = 1

Solution steps

- 3 x^{3} + 2 x^{2} + x = 0

Factor

- 3 x^{3} + 2 x^{2} + x : - x (3 x + 1) (x - 1)

- x (3 x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 1 = 0 or x - 1 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = - \frac{1}{3}, x = 1

(1 + x^{2})^{2} = 4 (1 - x^{2})

x^{3} + 6 = 12

x^{4} + 5 x^{2} - 50 = 0

128 x^{3} - 16 x = 0

x^{4} + a^{2} = 0

What are the solutions to the equation -3x^3+2x^2+x=0 ?
The solutions to the equation -3x^3+2x^2+x=0 are x=0,x=-1/3 ,x=1
Find the zeros of -3x^3+2x^2+x=0
The zeros of -3x^3+2x^2+x=0 are x=0,x=-1/3 ,x=1