What are the solutions to the equation 40000=17000(1+r)^{10} ?

The solutions to the equation 40000=17000(1+r)^{10} are r=\sqrt[10]{40/17}-1,r=-\sqrt[10]{40/17}-1

Find the zeros of 40000=17000(1+r)^{10}

The zeros of 40000=17000(1+r)^{10} are r=\sqrt[10]{40/17}-1,r=-\sqrt[10]{40/17}-1

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40000 = 17000 (1 + r)^{10}

Solution steps

40000 = 17000 (1 + r)^{10}

Switch sides

17000 (1 + r)^{10} = 40000

Divide both sides by

17000

(1 + r)^{10} = \frac{40}{17}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

0 = x^{3} + 5 x^{2} - 3 x - 15

282 = n^{85}

x^{3} (x^{2} - 5) + 4 x = 0

x (x - 2)^{2} = x

- 2 x^{3} + 5 = 21

What are the solutions to the equation 40000=17000(1+r)^{10} ?
The solutions to the equation 40000=17000(1+r)^{10} are r=\sqrt[10]{40/17}-1,r=-\sqrt[10]{40/17}-1
Find the zeros of 40000=17000(1+r)^{10}
The zeros of 40000=17000(1+r)^{10} are r=\sqrt[10]{40/17}-1,r=-\sqrt[10]{40/17}-1