What are the solutions to the equation x^3(x^2-5)+4x=0 ?

The solutions to the equation x^3(x^2-5)+4x=0 are x=0,x=-1,x=1,x=-2,x=2

Find the zeros of x^3(x^2-5)+4x=0

The zeros of x^3(x^2-5)+4x=0 are x=0,x=-1,x=1,x=-2,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} (x^{2} - 5) + 4 x = 0

x = 0, x = - 1, x = 1, x = - 2, x = 2

Solution steps

x^{3} (x^{2} - 5) + 4 x = 0

Factor

x^{3} (x^{2} - 5) + 4 x : x (x + 1) (x - 1) (x + 2) (x - 2)

x (x + 1) (x - 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 1, x = 1, x = - 2, x = 2

x (x - 2)^{2} = x

- 2 x^{3} + 5 = 21

x^{3} + 0.3 x^{2} + 0.3 x + 0.3 = 0

4 x^{4} + 4 x^{2} = 24

x^{8} - 2 x^{5} - 3 x^{2} = 0

What are the solutions to the equation x^3(x^2-5)+4x=0 ?
The solutions to the equation x^3(x^2-5)+4x=0 are x=0,x=-1,x=1,x=-2,x=2
Find the zeros of x^3(x^2-5)+4x=0
The zeros of x^3(x^2-5)+4x=0 are x=0,x=-1,x=1,x=-2,x=2