What are the solutions to the equation 4x^4+4x^2=24 ?

The solutions to the equation 4x^4+4x^2=24 are x=sqrt(2),x=-sqrt(2),x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of 4x^4+4x^2=24

The zeros of 4x^4+4x^2=24 are x=sqrt(2),x=-sqrt(2),x=sqrt(3)i,x=-sqrt(3)i

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4 x^{4} + 4 x^{2} = 24

x = 2, x = - 2, x = 3 i, x = - 3 i

Solution steps

4 x^{4} + 4 x^{2} = 24

Move

24

to the left side

4 x^{4} + 4 x^{2} - 24 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

4 u^{2} + 4 u - 24 = 0

Solve

4 u^{2} + 4 u - 24 = 0 : u = 2, u = - 3

u = 2, u = - 3

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 2 : x = 2, x = - 2

Solve

x^{2} = - 3 : x = 3 i, x = - 3 i

The solutions are

x = 2, x = - 2, x = 3 i, x = - 3 i

x^{8} - 2 x^{5} - 3 x^{2} = 0

x^{2} + 5 x - 81 = 5 x^{5} x

20 = [\frac{5 + ( 0.12 x )}{10}]^{20}

y^{3} + y^{2} - 3 y - 3 = 0

(x - 4) (x^{2} + 4 x + 16) = - 37

What are the solutions to the equation 4x^4+4x^2=24 ?
The solutions to the equation 4x^4+4x^2=24 are x=sqrt(2),x=-sqrt(2),x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of 4x^4+4x^2=24
The zeros of 4x^4+4x^2=24 are x=sqrt(2),x=-sqrt(2),x=sqrt(3)i,x=-sqrt(3)i