What are the solutions to the equation y^3+y^2-3y-3=0 ?

The solutions to the equation y^3+y^2-3y-3=0 are y=-1,y=-sqrt(3),y=sqrt(3)

Find the zeros of y^3+y^2-3y-3=0

The zeros of y^3+y^2-3y-3=0 are y=-1,y=-sqrt(3),y=sqrt(3)

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y^{3} + y^{2} - 3 y - 3 = 0

y = - 1, y = - 3, y = 3

Decimal Notation

y = - 1, y = - 1.73205 \dots, y = 1.73205 \dots

Solution steps

y^{3} + y^{2} - 3 y - 3 = 0

Factor

y^{3} + y^{2} - 3 y - 3 : (y + 1) (y + 3) (y - 3)

(y + 1) (y + 3) (y - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 1 = 0 or y + 3 = 0 or y - 3 = 0

Solve

y + 1 = 0 : y = - 1

Solve

y + 3 = 0 : y = - 3

Solve

y - 3 = 0 : y = 3

The solutions are

y = - 1, y = - 3, y = 3

(x - 4) (x^{2} + 4 x + 16) = - 37

L^{3} = 1927

(x - 3)^{4} = 21

w^{3} = 343

2 x^{8} - 3 + 5 = 15

What are the solutions to the equation y^3+y^2-3y-3=0 ?
The solutions to the equation y^3+y^2-3y-3=0 are y=-1,y=-sqrt(3),y=sqrt(3)
Find the zeros of y^3+y^2-3y-3=0
The zeros of y^3+y^2-3y-3=0 are y=-1,y=-sqrt(3),y=sqrt(3)