What are the solutions to the equation (x-3)^4=21 ?

The solutions to the equation (x-3)^4=21 are x=\sqrt[4]{21}+3,x=-\sqrt[4]{21}+3

Find the zeros of (x-3)^4=21

The zeros of (x-3)^4=21 are x=\sqrt[4]{21}+3,x=-\sqrt[4]{21}+3

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(x - 3)^{4} = 21

Decimal Notation

x = 5.14069 \dots, x = 0.85930 \dots

Solution steps

(x - 3)^{4} = 21

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

w^{3} = 343

2 x^{8} - 3 + 5 = 15

x^{3} x + 8 = - 4

x^{3} + 9 x^{2} + 17 x + 6 = 0

x^{6} + 16 = 0

What are the solutions to the equation (x-3)^4=21 ?
The solutions to the equation (x-3)^4=21 are x=\sqrt[4]{21}+3,x=-\sqrt[4]{21}+3
Find the zeros of (x-3)^4=21
The zeros of (x-3)^4=21 are x=\sqrt[4]{21}+3,x=-\sqrt[4]{21}+3