What are the solutions to the equation 2x^3-4x^2-x+2=0 ?

The solutions to the equation 2x^3-4x^2-x+2=0 are x=2,x=-1/(sqrt(2)),x= 1/(sqrt(2))

Find the zeros of 2x^3-4x^2-x+2=0

The zeros of 2x^3-4x^2-x+2=0 are x=2,x=-1/(sqrt(2)),x= 1/(sqrt(2))

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2 x^{3} - 4 x^{2} - x + 2 = 0

x = 2, x = - \frac{1}{2}, x = \frac{1}{2}

Solution steps

2 x^{3} - 4 x^{2} - x + 2 = 0

Factor

2 x^{3} - 4 x^{2} - x + 2 : (x - 2) (2 x + 1) (2 x - 1)

(x - 2) (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 2, x = - \frac{1}{2}, x = \frac{1}{2}

x^{4} - 2 x^{3} + 2 x^{2} - 8 x - 8 = 0

x^{4} - 6 x^{2} - 8 x - 3 = 0

λ^{3} - 2 λ^{2} - 5 λ + 6 = 0

(4 b)^{4} = 2 b

64 j^{6} - 27 j^{3} = 0

What are the solutions to the equation 2x^3-4x^2-x+2=0 ?
The solutions to the equation 2x^3-4x^2-x+2=0 are x=2,x=-1/(sqrt(2)),x= 1/(sqrt(2))
Find the zeros of 2x^3-4x^2-x+2=0
The zeros of 2x^3-4x^2-x+2=0 are x=2,x=-1/(sqrt(2)),x= 1/(sqrt(2))