What are the solutions to the equation x^4-6x^2-8x-3=0 ?

The solutions to the equation x^4-6x^2-8x-3=0 are x=-1,x=3

Find the zeros of x^4-6x^2-8x-3=0

The zeros of x^4-6x^2-8x-3=0 are x=-1,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} - 6 x^{2} - 8 x - 3 = 0

x = - 1, x = 3

Solution steps

x^{4} - 6 x^{2} - 8 x - 3 = 0

Factor

x^{4} - 6 x^{2} - 8 x - 3 : (x + 1)^{3} (x - 3)

(x + 1)^{3} (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = 3

λ^{3} - 2 λ^{2} - 5 λ + 6 = 0

(4 b)^{4} = 2 b

64 j^{6} - 27 j^{3} = 0

3 x^{4} - 3 x + 23 = 4

x^{3} (x^{2} - 10) = - 9 x

What are the solutions to the equation x^4-6x^2-8x-3=0 ?
The solutions to the equation x^4-6x^2-8x-3=0 are x=-1,x=3
Find the zeros of x^4-6x^2-8x-3=0
The zeros of x^4-6x^2-8x-3=0 are x=-1,x=3