What are the solutions to the equation 4x^3+3x^2+64x+48=0 ?

The solutions to the equation 4x^3+3x^2+64x+48=0 are x=-3/4 ,x=4i,x=-4i

Find the zeros of 4x^3+3x^2+64x+48=0

The zeros of 4x^3+3x^2+64x+48=0 are x=-3/4 ,x=4i,x=-4i

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4 x^{3} + 3 x^{2} + 64 x + 48 = 0

x = - \frac{3}{4}, x = 4 i, x = - 4 i

Solution steps

4 x^{3} + 3 x^{2} + 64 x + 48 = 0

Factor

4 x^{3} + 3 x^{2} + 64 x + 48 : (4 x + 3) (x^{2} + 16)

(4 x + 3) (x^{2} + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 3 = 0 or x^{2} + 16 = 0

Solve

4 x + 3 = 0 : x = - \frac{3}{4}

Solve

x^{2} + 16 = 0 : x = 4 i, x = - 4 i

The solutions are

x = - \frac{3}{4}, x = 4 i, x = - 4 i

x^{5} = 1 0^{- 2}

x, x^{5} + 3 x^{2} + 2 x + 1 = 0

2 x = λ \cdot 4 x^{3}

0.15 = (1 + \frac{x}{12})^{12} - 1

9 x^{3} + 54 x^{2} = x + 6

What are the solutions to the equation 4x^3+3x^2+64x+48=0 ?
The solutions to the equation 4x^3+3x^2+64x+48=0 are x=-3/4 ,x=4i,x=-4i
Find the zeros of 4x^3+3x^2+64x+48=0
The zeros of 4x^3+3x^2+64x+48=0 are x=-3/4 ,x=4i,x=-4i