What are the solutions to the equation 0.15=(1+x/(12))^{12}-1 ?

The solutions to the equation 0.15=(1+x/(12))^{12}-1 are x=0.14057…,x=-24.14057…

Find the zeros of 0.15=(1+x/(12))^{12}-1

The zeros of 0.15=(1+x/(12))^{12}-1 are x=0.14057…,x=-24.14057…

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0.15 = (1 + \frac{x}{12})^{12} - 1

x = 0.14057 \dots, x = - 24.14057 \dots

Solution steps

0.15 = (1 + \frac{x}{12})^{12} - 1

Switch sides

(1 + \frac{x}{12})^{12} - 1 = 0.15

Move

1

to the right side

(1 + \frac{x}{12})^{12} = 1.15

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 0.14057 \dots, x = - 24.14057 \dots

9 x^{3} + 54 x^{2} = x + 6

- 4 x^{3} + 6 x - 1 = 0

38 = h (2 h^{2} - 3 h)

(y - 1) (y^{2} + y + 2) = 0

5 = 3 - \frac{1}{10} b^{3} - 101 b

What are the solutions to the equation 0.15=(1+x/(12))^{12}-1 ?
The solutions to the equation 0.15=(1+x/(12))^{12}-1 are x=0.14057…,x=-24.14057…
Find the zeros of 0.15=(1+x/(12))^{12}-1
The zeros of 0.15=(1+x/(12))^{12}-1 are x=0.14057…,x=-24.14057…