What are the solutions to the equation (y-1)(y^2+y+2)=0 ?

The solutions to the equation (y-1)(y^2+y+2)=0 are y=1,y=-1/2+i(sqrt(7))/2 ,y=-1/2-i(sqrt(7))/2

Find the zeros of (y-1)(y^2+y+2)=0

The zeros of (y-1)(y^2+y+2)=0 are y=1,y=-1/2+i(sqrt(7))/2 ,y=-1/2-i(sqrt(7))/2

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(y - 1) (y^{2} + y + 2) = 0

y = 1, y = - \frac{1}{2} + i \frac{7}{2}, y = - \frac{1}{2} - i \frac{7}{2}

Solution steps

(y - 1) (y^{2} + y + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 1 = 0 or y^{2} + y + 2 = 0

Solve

y - 1 = 0 : y = 1

Solve

y^{2} + y + 2 = 0 : y = - \frac{1}{2} + i \frac{7}{2}, y = - \frac{1}{2} - i \frac{7}{2}

The solutions are

y = 1, y = - \frac{1}{2} + i \frac{7}{2}, y = - \frac{1}{2} - i \frac{7}{2}

5 = 3 - \frac{1}{10} b^{3} - 101 b

- 6 x^{3} + 36 x^{2} + 42 x = 0

x^{3} - 4 x + 3 = 2.8

x^{3} x = 18

9 = b^{4} - (- 5)

What are the solutions to the equation (y-1)(y^2+y+2)=0 ?
The solutions to the equation (y-1)(y^2+y+2)=0 are y=1,y=-1/2+i(sqrt(7))/2 ,y=-1/2-i(sqrt(7))/2
Find the zeros of (y-1)(y^2+y+2)=0
The zeros of (y-1)(y^2+y+2)=0 are y=1,y=-1/2+i(sqrt(7))/2 ,y=-1/2-i(sqrt(7))/2