What are the solutions to the equation x^3-4x+3=2.8 ?

The solutions to the equation x^3-4x+3=2.8 are x\approx 0.05003…,x\approx 1.97451…,x\approx-2.02454…

Find the zeros of x^3-4x+3=2.8

The zeros of x^3-4x+3=2.8 are x\approx 0.05003…,x\approx 1.97451…,x\approx-2.02454…

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x^{3} - 4 x + 3 = 2.8

x \approx 0.05003 \dots, x \approx 1.97451 \dots, x \approx - 2.02454 \dots

Solution steps

x^{3} - 4 x + 3 = 2.8

Multiply both sides by

10

10 x^{3} - 40 x + 30 = 28

Move

28

to the left side

10 x^{3} - 40 x + 2 = 0

Find one solution for

10 x^{3} - 40 x + 2 = 0

using Newton-Raphson:

x \approx 0.05003 \dots

Apply long division:

\frac{10 x ^{3} - 40 x + 2}{x - 0.05003 \dots} = 10 x^{2} + 0.50031 \dots x - 39.97496 \dots

10 x^{2} + 0.50031 \dots x - 39.97496 \dots \approx 0

Find one solution for

10 x^{2} + 0.50031 \dots x - 39.97496 \dots = 0

using Newton-Raphson:

x \approx 1.97451 \dots

Apply long division:

\frac{10 x ^{2} + 0.50031 \dots x - 39.97496 \dots}{x - 1.97451 \dots} = 10 x + 20.24546 \dots

10 x + 20.24546 \dots \approx 0

x \approx - 2.02454 \dots

The solutions are

x \approx 0.05003 \dots, x \approx 1.97451 \dots, x \approx - 2.02454 \dots

x^{3} x = 18

9 = b^{4} - (- 5)

x^{3} - 3 x^{2} - x - 5 = 0

x^{4} + 6 x^{3} + 11 x^{2} + 6 x - 48 = 0

5 x^{3} - 40 = 0

What are the solutions to the equation x^3-4x+3=2.8 ?
The solutions to the equation x^3-4x+3=2.8 are x\approx 0.05003…,x\approx 1.97451…,x\approx-2.02454…
Find the zeros of x^3-4x+3=2.8
The zeros of x^3-4x+3=2.8 are x\approx 0.05003…,x\approx 1.97451…,x\approx-2.02454…