What are the solutions to the equation 5x^3-40=0 ?

The solutions to the equation 5x^3-40=0 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of 5x^3-40=0

The zeros of 5x^3-40=0 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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5 x^{3} - 40 = 0

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

5 x^{3} - 40 = 0

Move

40

to the right side

5 x^{3} = 40

Divide both sides by

5

x^{3} = 8

For

x^{3} = f (a)

the solutions are

Simplify

x = 2, x = - 1 + 3 i, x = - 1 - 3 i

x^{3} - 6 x^{2} + 16 = 0

a^{3} + 9 a^{2} - 58 a + 8 = 0

t^{3} - 9 t = 0

25 x^{4} + 16 = 41 x^{2}

3 x^{3} + 15 x^{2} - 2 x = 10

What are the solutions to the equation 5x^3-40=0 ?
The solutions to the equation 5x^3-40=0 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of 5x^3-40=0
The zeros of 5x^3-40=0 are x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i