What are the solutions to the equation x^3-6x^2+16=0 ?

The solutions to the equation x^3-6x^2+16=0 are x=2,x=2(1+sqrt(3)),x=2(1-sqrt(3))

Find the zeros of x^3-6x^2+16=0

The zeros of x^3-6x^2+16=0 are x=2,x=2(1+sqrt(3)),x=2(1-sqrt(3))

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x^{3} - 6 x^{2} + 16 = 0

x = 2, x = 2 (1 + 3), x = 2 (1 - 3)

Decimal Notation

x = 2, x = 5.46410 \dots, x = - 1.46410 \dots

Solution steps

x^{3} - 6 x^{2} + 16 = 0

Factor

x^{3} - 6 x^{2} + 16 : (x - 2) (x^{2} - 4 x - 8)

(x - 2) (x^{2} - 4 x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} - 4 x - 8 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 4 x - 8 = 0 : x = 2 (1 + 3), x = 2 (1 - 3)

The solutions are

x = 2, x = 2 (1 + 3), x = 2 (1 - 3)

a^{3} + 9 a^{2} - 58 a + 8 = 0

t^{3} - 9 t = 0

25 x^{4} + 16 = 41 x^{2}

3 x^{3} + 15 x^{2} - 2 x = 10

(x + 4) \cdot (- 4 x^{2} + 4 x - 1) = 0

What are the solutions to the equation x^3-6x^2+16=0 ?
The solutions to the equation x^3-6x^2+16=0 are x=2,x=2(1+sqrt(3)),x=2(1-sqrt(3))
Find the zeros of x^3-6x^2+16=0
The zeros of x^3-6x^2+16=0 are x=2,x=2(1+sqrt(3)),x=2(1-sqrt(3))