What are the solutions to the equation x^3=-x^2+2x ?

The solutions to the equation x^3=-x^2+2x are x=0,x=1,x=-2

Find the zeros of x^3=-x^2+2x

The zeros of x^3=-x^2+2x are x=0,x=1,x=-2

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x^{3} = - x^{2} + 2 x

x = 0, x = 1, x = - 2

Solution steps

x^{3} = - x^{2} + 2 x

Move

2 x

to the left side

x^{3} - 2 x = - x^{2}

Move

x^{2}

to the left side

x^{3} - 2 x + x^{2} = 0

Factor

x^{3} - 2 x + x^{2} : x (x - 1) (x + 2)

x (x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 0, x = 1, x = - 2

9 x (2 x + 1)^{3} = 4 x (2 x + 1)

(4 x - 1) (5 x^{3} - 8.64) = 0

s^{5} + s^{2} + s = 0

x, 2 x^{4} + 3 = y^{2}

4 x^{3} - 52 x^{2} + 160 x - 100 = 0

What are the solutions to the equation x^3=-x^2+2x ?
The solutions to the equation x^3=-x^2+2x are x=0,x=1,x=-2
Find the zeros of x^3=-x^2+2x
The zeros of x^3=-x^2+2x are x=0,x=1,x=-2